on 05-17-2017 5:08 AM
Hi Experts,
I have a requirement to open a specific file folder by clicking a link in ALV grid.
As a Example, when I click a cell in the ALV grid, It should open a folder that I have given like, "C:\Users\anuradhawi\Documents" .
Is there anyway to do this.
I understand the question is outdated. But I will give my simple solution for open the directory, maybe it will be useful to someone:
CALL METHOD CL_GUI_FRONTEND_SERVICES=>EXECUTE
EXPORTING
APPLICATION = 'EXPLORER.EXE'
PARAMETER = 'C:\TEMP'
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