Find string after certain position

[former_member641612]

Dear Experts,

I have a string as follow

Data(v_string) = '12345***678**9'

I need to get the position of * after the number 8.

I cannot used:

FIND FIRST OCCURRENCE OF '*' in v_string match OFFSET pos

because it only return the position of the first * appearance which is the one after number 5.

I cannot use

SEARCH ... STARTING AT.... because it doesn't recognize *.

So is there away to do this?

Thanks

[cdprasanna]

Hi,

First find the position of occurrence of the number(in your example 8). Then try fetching the next character using string offset.

Thanks.

[former_member641612]

but the occurrence number is random not always eight,

even the length is also dynamic, it can be 1 to 100 but with two parts that consist of ****

[cdprasanna]

try some thing like below

DATA : lv_str TYPE string VALUE '123**34**',
       lv_offset TYPE i,
       lv_var1  TYPE string,
       lv_var2  TYPE string.

"now here i need to find the offset of * which is after 4
"sine i already know i need to find the occurence of * afetr 4 i will first devide it to two halfes and in second half  i will seacrh *

SPLIT lv_str AT '4' INTO lv_var1 lv_var2.
FIND FIRST OCCURRENCE OF '*' IN lv_var2 MATCH OFFSET lv_offset. 

[thanga_prakash]

Hi Samuel Indrajaya Try with REGEX, it can be achievable with REGEX, refer to below blogs on how to use REGEX, refer to demo program DEMO_REGEX_TOY

REGEX Demo program DEMO_REGEX_TOY

REGEX in ABAP

[DoanManhQuynh]

Then FIND ALL OCCURRENCES?

DATA(v_string) = '12345***678**9'.
DATA(_regex) = '[^\*]\*'.
FIND ALL OCCURRENCES OF REGEX _regex IN v_string RESULTS DATA(sub).

[Sandra_Rossi]

Basic algorithm question. Of course it's possible. I think it's possible in one statement if you use ABAP substring and find processing functions (see ABAP documentation).